-3(2t-2)=18

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Solution for -3(2t-2)=18 equation: 



-3(2t-2)=18

We move all terms to the left:

-3(2t-2)-(18)=0

We multiply parentheses

-6t+6-18=0

We add all the numbers together, and all the variables

-6t-12=0

We move all terms containing t to the left, all other terms to the right

-6t=12

t=12/-6

t=-2

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