X(2x-9)=(2x+5)(x-8)

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Solution for X(2x-9)=(2x+5)(x-8) equation: 



X(2X-9)=(2X+5)(X-8)

We move all terms to the left:

X(2X-9)-((2X+5)(X-8))=0

We multiply parentheses

2X^2-9X-((2X+5)(X-8))=0

We multiply parentheses ..

2X^2-((+2X^2-16X+5X-40))-9X=0



We calculate terms in parentheses: -((+2X^2-16X+5X-40)), so:

(+2X^2-16X+5X-40)

We get rid of parentheses

2X^2-16X+5X-40

We add all the numbers together, and all the variables

2X^2-11X-40

Back to the equation:

-(2X^2-11X-40)



We add all the numbers together, and all the variables

2X^2-9X-(2X^2-11X-40)=0

We get rid of parentheses

2X^2-2X^2-9X+11X+40=0

We add all the numbers together, and all the variables

2X+40=0

We move all terms containing X to the left, all other terms to the right

2X=-40

X=-40/2

X=-20

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