-3(20+7t)=4(-3t+12)

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Solution for -3(20+7t)=4(-3t+12) equation:



-3(20+7t)=4(-3t+12)
We move all terms to the left:
-3(20+7t)-(4(-3t+12))=0
We add all the numbers together, and all the variables
-3(7t+20)-(4(-3t+12))=0
We multiply parentheses
-21t-(4(-3t+12))-60=0
We calculate terms in parentheses: -(4(-3t+12)), so:
4(-3t+12)
We multiply parentheses
-12t+48
Back to the equation:
-(-12t+48)
We get rid of parentheses
-21t+12t-48-60=0
We add all the numbers together, and all the variables
-9t-108=0
We move all terms containing t to the left, all other terms to the right
-9t=108
t=108/-9
t=-12

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