(2-x)/8=(-3x-1)/6

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Solution for (2-x)/8=(-3x-1)/6 equation: 



(2-x)/8=(-3x-1)/6

We move all terms to the left:

(2-x)/8-((-3x-1)/6)=0

We add all the numbers together, and all the variables

(-1x+2)/8-((-3x-1)/6)=0

We calculate fractions


(-x)/()+(-((-3x-1)*8)/()=0



We calculate terms in parentheses: +(-((-3x-1)*8)/(), so:

-((-3x-1)*8)/(

We multiply all the terms by the denominator


-((-3x-1)*8)



We calculate terms in parentheses: -((-3x-1)*8), so:

(-3x-1)*8

We multiply parentheses

-24x-8

Back to the equation:

-(-24x-8)



We get rid of parentheses

24x+8

Back to the equation:

+(24x+8)



We add all the numbers together, and all the variables

(-1x)/()+(24x+8)=0

We get rid of parentheses

(-1x)/()+24x+8=0

We multiply all the terms by the denominator


(-1x)+24x*()+8*()=0

We add all the numbers together, and all the variables

(-1x)+24x*()=0

We get rid of parentheses

-1x+24x*()=0

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