-3(2-3x)=-6x-2x(x-3)

Solution for -3(2-3x)=-6x-2x(x-3) equation:

-3(2-3x)=-6x-2x(x-3)

We move all terms to the left:

-3(2-3x)-(-6x-2x(x-3))=0

We add all the numbers together, and all the variables

-3(-3x+2)-(-6x-2x(x-3))=0

We multiply parentheses

9x-(-6x-2x(x-3))-6=0


We calculate terms in parentheses: -(-6x-2x(x-3)), so:

-6x-2x(x-3)

We multiply parentheses

-2x^2-6x+6x

We add all the numbers together, and all the variables

-2x^2

Back to the equation:

-(-2x^2)


We get rid of parentheses

2x^2+9x-6=0

a = 2; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·2·(-6)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{129}}{2*2}=\frac{-9-\sqrt{129}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{129}}{2*2}=\frac{-9+\sqrt{129}}{4}
$