7(x+1)=2(3x+5)

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Solution for 7(x+1)=2(3x+5) equation: 



7(x+1)=2(3x+5)

We move all terms to the left:

7(x+1)-(2(3x+5))=0

We multiply parentheses

7x-(2(3x+5))+7=0



We calculate terms in parentheses: -(2(3x+5)), so:

2(3x+5)

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

7x-6x-10+7=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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