-3(14-10c)+12c=42c-42

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Solution for -3(14-10c)+12c=42c-42 equation: 



-3(14-10c)+12c=42c-42

We move all terms to the left:

-3(14-10c)+12c-(42c-42)=0

We add all the numbers together, and all the variables

-3(-10c+14)+12c-(42c-42)=0

We add all the numbers together, and all the variables

12c-3(-10c+14)-(42c-42)=0

We multiply parentheses

12c+30c-(42c-42)-42=0

We get rid of parentheses

12c+30c-42c+42-42=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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