X+(x+3)+(x+5)+(x+7)=56

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Solution for X+(x+3)+(x+5)+(x+7)=56 equation: 



X+(X+3)+(X+5)+(X+7)=56

We move all terms to the left:

X+(X+3)+(X+5)+(X+7)-(56)=0

We get rid of parentheses

X+X+X+X+3+5+7-56=0

We add all the numbers together, and all the variables

4X-41=0

We move all terms containing X to the left, all other terms to the right

4X=41

X=41/4

X=10+1/4

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