-3(10t+8)=-4(9t-19)+20

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Solution for -3(10t+8)=-4(9t-19)+20 equation: 



-3(10t+8)=-4(9t-19)+20

We move all terms to the left:

-3(10t+8)-(-4(9t-19)+20)=0

We multiply parentheses

-30t-(-4(9t-19)+20)-24=0



We calculate terms in parentheses: -(-4(9t-19)+20), so:

-4(9t-19)+20

We multiply parentheses

-36t+76+20

We add all the numbers together, and all the variables

-36t+96

Back to the equation:

-(-36t+96)



We get rid of parentheses

-30t+36t-96-24=0

We add all the numbers together, and all the variables

6t-120=0

We move all terms containing t to the left, all other terms to the right

6t=120

t=120/6

t=20

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