5(x+1)-2(x-3)=6(x-1)-1

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Solution for 5(x+1)-2(x-3)=6(x-1)-1 equation: 



5(x+1)-2(x-3)=6(x-1)-1

We move all terms to the left:

5(x+1)-2(x-3)-(6(x-1)-1)=0

We multiply parentheses

5x-2x-(6(x-1)-1)+5+6=0



We calculate terms in parentheses: -(6(x-1)-1), so:

6(x-1)-1

We multiply parentheses

6x-6-1

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We add all the numbers together, and all the variables

3x-(6x-7)+11=0

We get rid of parentheses

3x-6x+7+11=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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