-3(-6y+9)-7y=2(y-5)-2

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Solution for -3(-6y+9)-7y=2(y-5)-2 equation: 



-3(-6y+9)-7y=2(y-5)-2

We move all terms to the left:

-3(-6y+9)-7y-(2(y-5)-2)=0

We add all the numbers together, and all the variables

-7y-3(-6y+9)-(2(y-5)-2)=0

We multiply parentheses

-7y+18y-(2(y-5)-2)-27=0



We calculate terms in parentheses: -(2(y-5)-2), so:

2(y-5)-2

We multiply parentheses

2y-10-2

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)



We add all the numbers together, and all the variables

11y-(2y-12)-27=0

We get rid of parentheses

11y-2y+12-27=0

We add all the numbers together, and all the variables

9y-15=0

We move all terms containing y to the left, all other terms to the right

9y=15

y=15/9

y=1+2/3

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