5t-2(t-5)=29

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Solution for 5t-2(t-5)=29 equation: 



5t-2(t-5)=29

We move all terms to the left:

5t-2(t-5)-(29)=0

We multiply parentheses

5t-2t+10-29=0

We add all the numbers together, and all the variables

3t-19=0

We move all terms containing t to the left, all other terms to the right

3t=19

t=19/3

t=6+1/3

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