-2y+7+4y=3(2y-3)

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Solution for -2y+7+4y=3(2y-3) equation: 



-2y+7+4y=3(2y-3)

We move all terms to the left:

-2y+7+4y-(3(2y-3))=0

We add all the numbers together, and all the variables

2y-(3(2y-3))+7=0



We calculate terms in parentheses: -(3(2y-3)), so:

3(2y-3)

We multiply parentheses

6y-9

Back to the equation:

-(6y-9)



We get rid of parentheses

2y-6y+9+7=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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