5x-3(x-4)=4(x+2)

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Solution for 5x-3(x-4)=4(x+2) equation: 



5x-3(x-4)=4(x+2)

We move all terms to the left:

5x-3(x-4)-(4(x+2))=0

We multiply parentheses

5x-3x-(4(x+2))+12=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

2x-(4x+8)+12=0

We get rid of parentheses

2x-4x-8+12=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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