-2x2+42=-200

Solution for -2x2+42=-200 equation:

-2x^2+42=-200

We move all terms to the left:

-2x^2+42-(-200)=0

We add all the numbers together, and all the variables

-2x^2+242=0

a = -2; b = 0; c = +242;
Δ = b2-4ac
Δ = 02-4·(-2)·242
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*-2}=\frac{-44}{-4}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*-2}=\frac{44}{-4}
=-11
$