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1/3(12k+3)-(k+2)=0
Domain of the equation: 3(12k+3)!=0We get rid of parentheses
k∈R
1/3(12k+3)-k-2=0
We multiply all the terms by the denominator
-k*3(12k+3)-2*3(12k+3)+1=0
Wy multiply elements
-3k^2(1-6k(1+1=0
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