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-2x+5/6x=3
We move all terms to the left:
-2x+5/6x-(3)=0
Domain of the equation: 6x!=0We multiply all the terms by the denominator
x!=0/6
x!=0
x∈R
-2x*6x-3*6x+5=0
Wy multiply elements
-12x^2-18x+5=0
a = -12; b = -18; c = +5;
Δ = b2-4ac
Δ = -182-4·(-12)·5
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{141}}{2*-12}=\frac{18-2\sqrt{141}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{141}}{2*-12}=\frac{18+2\sqrt{141}}{-24} $
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