1/3(x+x+6)=2/3(x-9)

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Solution for 1/3(x+x+6)=2/3(x-9) equation: 



1/3(x+x+6)=2/3(x-9)

We move all terms to the left:

1/3(x+x+6)-(2/3(x-9))=0



Domain of the equation: 3(x+x+6)!=0

x∈R





Domain of the equation: 3(x-9))!=0

x∈R



We add all the numbers together, and all the variables

1/3(2x+6)-(2/3(x-9))=0

We calculate fractions


(3xx/(3(2x+6)*3(x-9)))+(-6x2/(3(2x+6)*3(x-9)))=0



We calculate terms in parentheses: +(3xx/(3(2x+6)*3(x-9))), so:

3xx/(3(2x+6)*3(x-9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-6x2/(3(2x+6)*3(x-9))), so:

-6x2/(3(2x+6)*3(x-9))

We multiply all the terms by the denominator


-6x2

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

+(-6x^2)



We get rid of parentheses

-6x^2+3xx=0

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