-2x(x+5)=-35+4x

Solution for -2x(x+5)=-35+4x equation:

-2x(x+5)=-35+4x

We move all terms to the left:

-2x(x+5)-(-35+4x)=0

We add all the numbers together, and all the variables

-2x(x+5)-(4x-35)=0

We multiply parentheses

-2x^2-10x-(4x-35)=0

We get rid of parentheses

-2x^2-10x-4x+35=0

We add all the numbers together, and all the variables

-2x^2-14x+35=0

a = -2; b = -14; c = +35;
Δ = b2-4ac
Δ = -142-4·(-2)·35
Δ = 476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{476}=\sqrt{4*119}=\sqrt{4}*\sqrt{119}=2\sqrt{119}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{119}}{2*-2}=\frac{14-2\sqrt{119}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{119}}{2*-2}=\frac{14+2\sqrt{119}}{-4}
$