-2x(5x-4)-(5x-4)=(5x-4)(5x-4)

Solution for -2x(5x-4)-(5x-4)=(5x-4)(5x-4) equation:

-2x(5x-4)-(5x-4)=(5x-4)(5x-4)

We move all terms to the left:

-2x(5x-4)-(5x-4)-((5x-4)(5x-4))=0

We multiply parentheses

-10x^2+8x-(5x-4)-((5x-4)(5x-4))=0

We get rid of parentheses

-10x^2+8x-5x-((5x-4)(5x-4))+4=0

We multiply parentheses ..

-10x^2-((+25x^2-20x-20x+16))+8x-5x+4=0


We calculate terms in parentheses: -((+25x^2-20x-20x+16)), so:

(+25x^2-20x-20x+16)

We get rid of parentheses

25x^2-20x-20x+16

We add all the numbers together, and all the variables

25x^2-40x+16

Back to the equation:

-(25x^2-40x+16)


We add all the numbers together, and all the variables

-10x^2+3x-(25x^2-40x+16)+4=0

We get rid of parentheses

-10x^2-25x^2+3x+40x-16+4=0

We add all the numbers together, and all the variables

-35x^2+43x-12=0

a = -35; b = 43; c = -12;
Δ = b2-4ac
Δ = 432-4·(-35)·(-12)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-13}{2*-35}=\frac{-56}{-70}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+13}{2*-35}=\frac{-30}{-70}
=3/7
$