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-2x(5x-1)=3(x+1)
We move all terms to the left:
-2x(5x-1)-(3(x+1))=0
We multiply parentheses
-10x^2+2x-(3(x+1))=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
-10x^2+2x-3x-3=0
We add all the numbers together, and all the variables
-10x^2-1x-3=0
a = -10; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·(-10)·(-3)
Δ = -119
Delta is less than zero, so there is no solution for the equation
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