2(y-4)-4y=2

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Solution for 2(y-4)-4y=2 equation:



2(y-4)-4y=2
We move all terms to the left:
2(y-4)-4y-(2)=0
We add all the numbers together, and all the variables
-4y+2(y-4)-2=0
We multiply parentheses
-4y+2y-8-2=0
We add all the numbers together, and all the variables
-2y-10=0
We move all terms containing y to the left, all other terms to the right
-2y=10
y=10/-2
y=-5

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