-2x(3x-4)=(6x-8)

Solution for -2x(3x-4)=(6x-8) equation:

-2x(3x-4)=(6x-8)

We move all terms to the left:

-2x(3x-4)-((6x-8))=0

We multiply parentheses

-6x^2+8x-((6x-8))=0


We calculate terms in parentheses: -((6x-8)), so:

(6x-8)

We get rid of parentheses

6x-8

Back to the equation:

-(6x-8)


We get rid of parentheses

-6x^2+8x-6x+8=0

We add all the numbers together, and all the variables

-6x^2+2x+8=0

a = -6; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-6)·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*-6}=\frac{-16}{-12}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*-6}=\frac{12}{-12}
=-1
$