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-2x(-x+1)+3x+3=26
We move all terms to the left:
-2x(-x+1)+3x+3-(26)=0
We add all the numbers together, and all the variables
-2x(-1x+1)+3x+3-26=0
We add all the numbers together, and all the variables
3x-2x(-1x+1)-23=0
We multiply parentheses
2x^2+3x-2x-23=0
We add all the numbers together, and all the variables
2x^2+x-23=0
a = 2; b = 1; c = -23;
Δ = b2-4ac
Δ = 12-4·2·(-23)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{185}}{2*2}=\frac{-1-\sqrt{185}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{185}}{2*2}=\frac{-1+\sqrt{185}}{4} $
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