-2v2-8v=-64

Solution for -2v2-8v=-64 equation:

-2v^2-8v=-64

We move all terms to the left:

-2v^2-8v-(-64)=0

We add all the numbers together, and all the variables

-2v^2-8v+64=0

a = -2; b = -8; c = +64;
Δ = b2-4ac
Δ = -82-4·(-2)·64
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*-2}=\frac{-16}{-4}
=+4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*-2}=\frac{32}{-4}
=-8
$