4a2=-8+129

Solution for 4a2=-8+129 equation:

4a^2=-8+129

We move all terms to the left:

4a^2-(-8+129)=0

We add all the numbers together, and all the variables

4a^2-121=0

a = 4; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·4·(-121)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*4}=\frac{-44}{8}
=-5+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*4}=\frac{44}{8}
=5+1/2
$