-2v(v-5)(v+5)=0

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Solution for -2v(v-5)(v+5)=0 equation: 



-2v(v-5)(v+5)=0

We use the square of the difference formula

v^2+25=0

a = 1; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·1·25
Δ = -100
Delta is less than zero, so there is no solution for the equation

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