7(x-3)=4(x+5)x=

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Solution for 7(x-3)=4(x+5)x= equation: 



7(x-3)=4(x+5)x=

We move all terms to the left:

7(x-3)-(4(x+5)x)=0

We multiply parentheses

7x-(4(x+5)x)-21=0



We calculate terms in parentheses: -(4(x+5)x), so:

4(x+5)x

We multiply parentheses

4x^2+20x

Back to the equation:

-(4x^2+20x)



We get rid of parentheses

-4x^2+7x-20x-21=0

We add all the numbers together, and all the variables

-4x^2-13x-21=0

a = -4; b = -13; c = -21;
Δ = b2-4ac
Δ = -132-4·(-4)·(-21)
Δ = -167
Delta is less than zero, so there is no solution for the equation

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