-2u(u-3)(U+8)=0

Solution for -2u(u-3)(U+8)=0 equation:

-2u(u-3)(+8)=0

We add all the numbers together, and all the variables

-2u(u-3)8=0

We multiply parentheses

-16u^2+48u=0

a = -16; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-16)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-16}=\frac{-96}{-32}
=+3
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-16}=\frac{0}{-32}
=0
$