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(5z+8)(5+z)=0
We add all the numbers together, and all the variables
(5z+8)(z+5)=0
We multiply parentheses ..
(+5z^2+25z+8z+40)=0
We get rid of parentheses
5z^2+25z+8z+40=0
We add all the numbers together, and all the variables
5z^2+33z+40=0
a = 5; b = 33; c = +40;
Δ = b2-4ac
Δ = 332-4·5·40
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-17}{2*5}=\frac{-50}{10} =-5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+17}{2*5}=\frac{-16}{10} =-1+3/5 $
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