-2j-5(j+2)=-(3j-1)

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Solution for -2j-5(j+2)=-(3j-1) equation: 



-2j-5(j+2)=-(3j-1)

We move all terms to the left:

-2j-5(j+2)-(-(3j-1))=0

We multiply parentheses

-2j-5j-(-(3j-1))-10=0



We calculate terms in parentheses: -(-(3j-1)), so:

-(3j-1)

We get rid of parentheses

-3j+1

Back to the equation:

-(-3j+1)



We add all the numbers together, and all the variables

-7j-(-3j+1)-10=0

We get rid of parentheses

-7j+3j-1-10=0

We add all the numbers together, and all the variables

-4j-11=0

We move all terms containing j to the left, all other terms to the right

-4j=11

j=11/-4

j=-2+3/4

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