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2x-1/3x+1=14
We move all terms to the left:
2x-1/3x+1-(14)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2x-1/3x-13=0
We multiply all the terms by the denominator
2x*3x-13*3x-1=0
Wy multiply elements
6x^2-39x-1=0
a = 6; b = -39; c = -1;
Δ = b2-4ac
Δ = -392-4·6·(-1)
Δ = 1545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1545}}{2*6}=\frac{39-\sqrt{1545}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1545}}{2*6}=\frac{39+\sqrt{1545}}{12} $
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