-2=(1/6)(10-x)=2

Solution for -2=(1/6)(10-x)=2 equation:

-2=(1/6)(10-x)=2

We move all terms to the left:

-2-((1/6)(10-x))=0


Domain of the equation: 6)(10-x))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/6)(-1x+10))-2=0

We multiply parentheses ..

-((-1x^2+1/6*10))-2=0

We multiply all the terms by the denominator


-((-1x^2+1-2*6*10))=0


We calculate terms in parentheses: -((-1x^2+1-2*6*10)), so:

(-1x^2+1-2*6*10)

We get rid of parentheses

-1x^2+1-2*6*10

We add all the numbers together, and all the variables

-1x^2-119

Back to the equation:

-(-1x^2-119)


We get rid of parentheses

1x^2+119=0

We add all the numbers together, and all the variables

x^2+119=0

a = 1; b = 0; c = +119;
Δ = b2-4ac
Δ = 02-4·1·119
Δ = -476
Delta is less than zero, so there is no solution for the equation