t(t+3)=t2+9

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Solution for t(t+3)=t2+9 equation: 



t(t+3)=t2+9

We move all terms to the left:

t(t+3)-(t2+9)=0

We add all the numbers together, and all the variables

-(+t^2+9)+t(t+3)=0

We multiply parentheses

-(+t^2+9)+t^2+3t=0

We get rid of parentheses

-t^2+t^2+3t-9=0

We add all the numbers together, and all the variables

3t-9=0

We move all terms containing t to the left, all other terms to the right

3t=9

t=9/3

t=3

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