-297+5x+2x2=0

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Solution for -297+5x+2x2=0 equation:



-297+5x+2x^2=0
a = 2; b = 5; c = -297;
Δ = b2-4ac
Δ = 52-4·2·(-297)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-49}{2*2}=\frac{-54}{4} =-13+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+49}{2*2}=\frac{44}{4} =11 $

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