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-28x+5x(3x-7)+12-8(x-2)+3x(2x-1)-(4x+2)=x
We move all terms to the left:
-28x+5x(3x-7)+12-8(x-2)+3x(2x-1)-(4x+2)-(x)=0
We add all the numbers together, and all the variables
-29x+5x(3x-7)-8(x-2)+3x(2x-1)-(4x+2)+12=0
We multiply parentheses
15x^2+6x^2-29x-35x-8x-3x-(4x+2)+16+12=0
We get rid of parentheses
15x^2+6x^2-29x-35x-8x-3x-4x-2+16+12=0
We add all the numbers together, and all the variables
21x^2-79x+26=0
a = 21; b = -79; c = +26;
Δ = b2-4ac
Δ = -792-4·21·26
Δ = 4057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{4057}}{2*21}=\frac{79-\sqrt{4057}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{4057}}{2*21}=\frac{79+\sqrt{4057}}{42} $
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