-28=-6+2(y-2)

Solution for -28=-6+2(y-2) equation:

-28=-6+2(y-2)

We move all terms to the left:

-28-(-6+2(y-2))=0


We calculate terms in parentheses: -(-6+2(y-2)), so:

-6+2(y-2)

determiningTheFunctionDomain
2(y-2)-6

We multiply parentheses

2y-4-6

We add all the numbers together, and all the variables

2y-10

Back to the equation:

-(2y-10)


We get rid of parentheses

-2y+10-28=0

We add all the numbers together, and all the variables

-2y-18=0

We move all terms containing y to the left, all other terms to the right

-2y=18

y=18/-2

y=-9