3(7b-15)=17(b-3)

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Solution for 3(7b-15)=17(b-3) equation: 



3(7b-15)=17(b-3)

We move all terms to the left:

3(7b-15)-(17(b-3))=0

We multiply parentheses

21b-(17(b-3))-45=0



We calculate terms in parentheses: -(17(b-3)), so:

17(b-3)

We multiply parentheses

17b-51

Back to the equation:

-(17b-51)



We get rid of parentheses

21b-17b+51-45=0

We add all the numbers together, and all the variables

4b+6=0

We move all terms containing b to the left, all other terms to the right

4b=-6

b=-6/4

b=-1+1/2

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