-28-6b=2-6(1+2b)

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Solution for -28-6b=2-6(1+2b) equation: 



-28-6b=2-6(1+2b)

We move all terms to the left:

-28-6b-(2-6(1+2b))=0

We add all the numbers together, and all the variables

-6b-(2-6(2b+1))-28=0



We calculate terms in parentheses: -(2-6(2b+1)), so:

2-6(2b+1)

determiningTheFunctionDomain
-6(2b+1)+2

We multiply parentheses

-12b-6+2

We add all the numbers together, and all the variables

-12b-4

Back to the equation:

-(-12b-4)



We get rid of parentheses

-6b+12b+4-28=0

We add all the numbers together, and all the variables

6b-24=0

We move all terms containing b to the left, all other terms to the right

6b=24

b=24/6

b=4

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