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9(x-3)=2(x-3)
We move all terms to the left:
9(x-3)-(2(x-3))=0
We multiply parentheses
9x-(2(x-3))-27=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
9x-2x+6-27=0
We add all the numbers together, and all the variables
7x-21=0
We move all terms containing x to the left, all other terms to the right
7x=21
x=21/7
x=3
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