-28-5n=-6n(n+5)

Solution for -28-5n=-6n(n+5) equation:

-28-5n=-6n(n+5)

We move all terms to the left:

-28-5n-(-6n(n+5))=0


We calculate terms in parentheses: -(-6n(n+5)), so:

-6n(n+5)

We multiply parentheses

-6n^2-30n

Back to the equation:

-(-6n^2-30n)


We get rid of parentheses

6n^2+30n-5n-28=0

We add all the numbers together, and all the variables

6n^2+25n-28=0

a = 6; b = 25; c = -28;
Δ = b2-4ac
Δ = 252-4·6·(-28)
Δ = 1297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1297}}{2*6}=\frac{-25-\sqrt{1297}}{12}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1297}}{2*6}=\frac{-25+\sqrt{1297}}{12}
$