-6(8v-2)=4v-40

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Solution for -6(8v-2)=4v-40 equation: 



-6(8v-2)=4v-40

We move all terms to the left:

-6(8v-2)-(4v-40)=0

We multiply parentheses

-48v-(4v-40)+12=0

We get rid of parentheses

-48v-4v+40+12=0

We add all the numbers together, and all the variables

-52v+52=0

We move all terms containing v to the left, all other terms to the right

-52v=-52

v=-52/-52

v=1

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