-27=3(y-3)-5y

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Solution for -27=3(y-3)-5y equation: 



-27=3(y-3)-5y

We move all terms to the left:

-27-(3(y-3)-5y)=0



We calculate terms in parentheses: -(3(y-3)-5y), so:

3(y-3)-5y

We add all the numbers together, and all the variables

-5y+3(y-3)

We multiply parentheses

-5y+3y-9

We add all the numbers together, and all the variables

-2y-9

Back to the equation:

-(-2y-9)



We get rid of parentheses

2y+9-27=0

We add all the numbers together, and all the variables

2y-18=0

We move all terms containing y to the left, all other terms to the right

2y=18

y=18/2

y=9

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