-27+6y=3(y-4)

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Solution for -27+6y=3(y-4) equation: 



-27+6y=3(y-4)

We move all terms to the left:

-27+6y-(3(y-4))=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We get rid of parentheses

6y-3y+12-27=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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