3x-(x-2)/3=4-(x-1)/4

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Solution for 3x-(x-2)/3=4-(x-1)/4 equation: 



3x-(x-2)/3=4-(x-1)/4

We move all terms to the left:

3x-(x-2)/3-(4-(x-1)/4)=0

We calculate fractions


3x+(-x)/()+(-(4-(x-1)*3)/()=0



We calculate terms in parentheses: +(-(4-(x-1)*3)/(), so:

-(4-(x-1)*3)/(

We multiply all the terms by the denominator


-(4-(x-1)*3)



We calculate terms in parentheses: -(4-(x-1)*3), so:

4-(x-1)*3

determiningTheFunctionDomain
-(x-1)*3+4

We multiply parentheses

-3x+3+4

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)



We get rid of parentheses

3x-7

Back to the equation:

+(3x-7)



We add all the numbers together, and all the variables

3x+(-1x)/()+(3x-7)=0

We get rid of parentheses

3x+(-1x)/()+3x-7=0

We multiply all the terms by the denominator


3x*()+(-1x)+3x*()-7*()=0

We add all the numbers together, and all the variables

3x*()+(-1x)+3x*()=0

We get rid of parentheses

3x*()-1x+3x*()=0

We add all the numbers together, and all the variables

-1x+3x*()+3x*()=0

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