-26=4(3x-2)+3(x-1)

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Solution for -26=4(3x-2)+3(x-1) equation: 



-26=4(3x-2)+3(x-1)

We move all terms to the left:

-26-(4(3x-2)+3(x-1))=0



We calculate terms in parentheses: -(4(3x-2)+3(x-1)), so:

4(3x-2)+3(x-1)

We multiply parentheses

12x+3x-8-3

We add all the numbers together, and all the variables

15x-11

Back to the equation:

-(15x-11)



We get rid of parentheses

-15x+11-26=0

We add all the numbers together, and all the variables

-15x-15=0

We move all terms containing x to the left, all other terms to the right

-15x=15

x=15/-15

x=-1

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