2t+31=5-(t-2)

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Solution for 2t+31=5-(t-2) equation: 



2t+31=5-(t-2)

We move all terms to the left:

2t+31-(5-(t-2))=0



We calculate terms in parentheses: -(5-(t-2)), so:

5-(t-2)

determiningTheFunctionDomain
-(t-2)+5

We get rid of parentheses

-t+2+5

We add all the numbers together, and all the variables

-1t+7

Back to the equation:

-(-1t+7)



We get rid of parentheses

2t+1t-7+31=0

We add all the numbers together, and all the variables

3t+24=0

We move all terms containing t to the left, all other terms to the right

3t=-24

t=-24/3

t=-8

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