-25x2-50x+200=2x2-10

Solution for -25x2-50x+200=2x2-10 equation:

-25x^2-50x+200=2x^2-10

We move all terms to the left:

-25x^2-50x+200-(2x^2-10)=0

We get rid of parentheses

-25x^2-2x^2-50x+10+200=0

We add all the numbers together, and all the variables

-27x^2-50x+210=0

a = -27; b = -50; c = +210;
Δ = b2-4ac
Δ = -502-4·(-27)·210
Δ = 25180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25180}=\sqrt{4*6295}=\sqrt{4}*\sqrt{6295}=2\sqrt{6295}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{6295}}{2*-27}=\frac{50-2\sqrt{6295}}{-54}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{6295}}{2*-27}=\frac{50+2\sqrt{6295}}{-54}
$