-25x2+500x-2475=0

Solution for -25x2+500x-2475=0 equation:

-25x^2+500x-2475=0

a = -25; b = 500; c = -2475;
Δ = b2-4ac
Δ = 5002-4·(-25)·(-2475)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-50}{2*-25}=\frac{-550}{-50}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+50}{2*-25}=\frac{-450}{-50}
=+9
$