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-25x^2+500x-1875=0
a = -25; b = 500; c = -1875;
Δ = b2-4ac
Δ = 5002-4·(-25)·(-1875)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-250}{2*-25}=\frac{-750}{-50} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+250}{2*-25}=\frac{-250}{-50} =+5 $
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